How do you simplify the expression 1/cotx? | Socratic
2018年3月17日 · tanx Know your reciprocal identities: tanx=1/cotx cotx=1/tanx secx=1/cosx cosx=1/secx sinx=1/cscx cscx=1/sinx
How do you verify cotx-tanx=2cot2x? - Socratic
2015年7月24日 · Using the relationship between tan/cot and sin-cos, plus the double angle formulae for sin and cos. (as requested)
How do you prove tan(x + (pi/2)) = -cotx? - Socratic
2015年4月16日 · We can not simply use the tangent of a sum formula, because tan (pi/2) does not exist. See other answer for using the sum formula. So use tan theta = sin theta / cos theta and the sum formulas for sine and cosine. tan(x + pi/2) = (sin(x + pi/2))/(cos(x + pi/2)) = (sinx cos(pi/2)+cosx sin(pi/2))/(cosx cos(pi/2)-sinx sin(pi/2)) = (0+cosx)/(0-sinx ) = - cosx/sinx = -cotx
How do you determine the limit of cot(x) as x approaches pi
2016年7月1日 · #lim_{x to pi^-} cot x# #= lim_{x to pi^-} cosx/sinx# let #x = pi - eta#, where #0 < eta < < 1#. so #= lim_{x to pi^-} cosx/sinx = lim_{eta to 0} cos(pi - eta)/sin(pi ...
Cscx/cotx+tanx= cosx? - Socratic
2018年3月28日 · To prove the identity, you'll need these four, more basic identities: cscx=1/sinx cotx=cosx/sinx tanx=sinx/cosx sin^2x+cos^2x=1 To start the proof, use these identities to write everything in terms of sine and cosine.
How do you prove tanx + cotx = secx cscx? - Socratic
2015年11月28日 · Given: #tan x+ cot x= sec x *cscx# Start on the right hand side, change it to #sinx#; #cosx#. #sinx/cosx + cosx/sinx = sec x *csc x#
How to simplify sin x cot x? - Socratic
2017年5月2日 · cosx cotx can be rewritten as cosx/sinx So we can rewrite our problem as: color(red)(sinx )(cos x/color(red)(sin x)) The sinx cancels leaving cosx
How do you differentiate #f(x)=cotx/(1-sinx)#? - Socratic
2017年7月5日 · In order to derive #cot(x)/(1-sin(x))#, you need to apply the quotient rule first.. The quotient rule states this:
How to you simplify cotx+tanx? - Socratic
2017年12月7日 · If we write #cot(x)# as #1/tan(x)#, we get: #cot(x)+tan(x)=1/tan(x)+tan(x)# Then we bring under a common denominator:
What is the limit as x approaches 0 of cotx/lnx? - Socratic
2014年12月11日 · Since ln x is only defined when x>0, we can only talk about the right-hand limit: lim_{x to 0^+}{cot x}/{ln x} Since {(lim_{x to 0^+}cot x=lim_{x to 0^+}{cos x}/{sin ...