2024年3月9日 · These calculations are from these notes from MIT OCW's 8.02 "Electromagnetism", on page 27. We can represent the location of a point ##P## on the surface of the Earth using spherical coordinates Let the ##z##-axis be the Earth's rotation axis, and the ##x##-axis passes through the prime...

2010年1月27日 · A uniformly charged solid sphere of radius R carries a total charge Q, and is set spinning with angular velocity [itex] \omega [/itex] about the z axis. (a) What is the magnetic dipole moment of the sphere? Homework Equations [tex] \vec{m} = I \int d\vec{a} [/tex] The Attempt at a Solution having a lot of difficulty with this stuff

2024年11月2日 · It is a very similar procedure that we do with scalar potential for electric sources, but there the first non-vanishing term is the electric monopole term, and here is the magnetic dipole term. This is why sometimes we say "magnetic moment" referring just to dipole term. If the source has negligible volume, you can assume it is about dipole moment.

Every electron has two types of magnetic dipole moment, namely spin magnetic dipole moment and orbital magnetic dipole moment. There are several electrons in an atom and most electrons cancel out each other's magnetic moment. When all the electrons cancel out neatly, the total magnetic moment of the atom is zero.

2021年1月24日 · I also want to know and understand whether the origin of magnetic dipole moment, whether orbital or spin, can be explained classically. $\endgroup$ – Solidification Commented Jan 24, 2021 at 15:30

2015年5月15日 · In this case, the the general formula for the magnetic dipole moment of the configuration is $$ \vec{\mu} = \frac{1}{2} \int \vec{r} \times \vec{J} \,d^3r. $$ (Showing that this reduces to the above formula for a flat planar loop is left as an exercise to the reader.)

2021年5月27日 · The negative sign indicates the tendency of the dipole to be aligned with the magnetic field; a dipole transverse to its local magnetic field has more energy than when it's parallel to the field. Looking at your computation, it looks like the confusion lies in how you've defined $\theta$ .

$\begingroup$ If magnetic charges would exist in Maxwell equations: $\mathbf{\nabla}.\mathbf{B} = 4 \pi \rho_m$ where $\rho_m$ is the magnetic charge density, then the magnetic dipole solution can be obtained exactly in the same way an electric dipole is obtained in the standard Maxwell theory; i.e., by taking two opposite infinitesimally ...

2023年5月6日 · A magnetic dipole μ, which is located at the origin of a coordinate system, generates a magnetic field in ...

2024年3月8日 · 2) The magnetic dipole moment is a vector normal to the surface enclosed by the loop (using right-hand rule relative to the current) and has magnitude ##IA##. $$\mu=IA\hat{n}$$ 3) The field of a magnetic dipole resembles that of a bar magnet. The bar magnet is also referred to as a magnetic dipole. Ok, we have these three things for our current ...