2015年9月3日 · There are two basic ways you can multiply a vector, the dot product, as demonstrated in the link Dot Product, which gives you a scalar, no matter if you are multiplying …

2012年8月1日 · 2) The dot product gives a scalar result: <v1, v2, v3>.<u1, u2, u3>= v1u1+ v2u2+ v3u3 so that the square would be <v1, v2, v3>^2= v1^2+ v2^2+ v3^2 a scalar (number) not a …

2014年12月20日 · Information one place states that a vector multiplied by itself is the same as the dot product of a vector with itself: $\vec{c}\cdot\vec{c}$. Other places I've found information …

So this is a vector field whose divergence is zero everywhere except the origin, where its divergence...well, diverges. That all certainly sounds like a delta function. Typically, one uses …

Is there a notation for element-wise (or pointwise) operations? For example, take the element-wise product of two vectors x and y (in Matlab, x .* y, in numpy x*y), producing a new vector of …

2019年6月25日 · But from the definition of vector Laplacian we are saying that $\nabla.(\nabla F)$ is defined that is the operation in the braces gradient of a vector field is also defined . So finally …

2018年4月5日 · $\begingroup$ Hello, just saw your answer, but I'm a bit confused about the part of the Wishart distribution, which seems to be the distribution of a certain types of random …

As tensors that operates on one vector space and its dual space are a sort of special case of non-square tensors, do they have a particular name? (for example like a ring is a semiring with the …

2020年2月5日 · Every square matrix has a characteristic polynomial. In the domain of real numbers, not every polynomial has real roots and so not every matrix has an eigenvalue, …

The one you used is the Euclidean distance, which is the square root of the sum of the squares of the components. Your computation is correct, and it is the Euclidean distance from the origin …