as invese of any matrix is given by a formula; a-1=[1/|a|]x[adj of a] but here we proof by general method. let k is inverse of identity matrix i then we khow that as, ki=ik=i also,ki=ik=k so,i=k or [i=i-1] so inverse of identity matrix is identity matrix. ** thanks**

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2018年4月30日 · Is it true that the inverse of any identity matrix is itself? From my working, It appeared true for 1x1's to 3x3's.

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2016年6月16日 · $\begingroup$ You have to use that these are effective matrices: associativity and existence of the identity are not enough to prove that right invertibility is equivalent to left invertibility. $\endgroup$

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